Скачать с ютуб Solutions Chemistry Class 12 | Chapter 2 | CBSE NEET JEE в хорошем качестве

Solutions Chemistry Class 12 | Chapter 2 | CBSE NEET JEE

➡️Buy One-Shots Pendrive : https://www.amazon.in/dp/B0BZWHRKZJ?r... ➡️Free Notes:http://bit.ly/Class12ChemistrySolutio... ➡️Free NCERT Solutions:http://bit.ly/Class12ChemistrySolutio... ➡️Join Telegram: t.me/LearnoHub12 ➡️Ask Doubts:https://www.examfear.com/question/ #LearnoHubChemistry#FREEhaiParBESThai #SabkoSamajhAayega #CBSEClass12Chemistry Timestamps: 0:00 Introduction 0:45 Solutions 5:53 Solutions:Solvent&Solute 8:55 Solutions:BinarySolutions 9:29 Solutions:Types 9:53 Solutions:GaseousSolution 11:25 Solutions:Liquid Solution 12:37 Solutions:Solid Solution 14:45 Solutions:Concentration 17:15 Solutions:Quantitative concentration 17:52 Mass Percentage 19:36 Volume Percentage 21:05 Mass by VolumePercentage 22:16 Parts per million 25:30 Mole Fraction 27:17 Mole Fraction:Example 32:57 Molarity 34:58 Molarity:Example 38:07 Molality 40:42 Molality:Example 43:44 Solutions:Quantitative Concentration 45:50 Problem 1 48:08 Problem 2 56:17 Problem 3 In this video we will cover: 1.NCERT solutions class 12 Chemistry chapter 2 solutions 2.NCERT Class 12 Chemistry chapter 2 Solutions notes 3.What are solutions? 4.Difference between solution and solvent. 5.Explain binary solutions. 6.Different types of solutions. 7.Calculate the mole fraction of ethylene glycol (C2H6O2) in a solution containing 20% of C2H6O2 by mass. 8.Calculate the molarity of a solution containing 5 g of NaOH in 450 mL solution 9.Calculate molality of 2.5 g of ethanoic acid (CH3COOH) in 75 g of benzene 10.Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride 11.Solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL–1, then what shall be the molarity of the solution? 13.A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution. LearnoHub.com (formerly called ExamFear Education) is a Free Education platform with more than 6000 videos on Physics, Chemistry, Maths, Biology, English, Science experiments, tips & tricks and motivational videos for Classes 6 to 12. Learn for Free! ➡️Website: http://www.learnohub.com ➡️Facebook: https://bit.ly/LearnoHubFB ➡️Instagram: https://bit.ly/LearnoHubInsta Get Our Videos in Pendrives: Class 12 - https://bit.ly/LHPenDrive12 Post your doubts here: https://www.examfear.com/question/ Join our Telegram Group: LearnoHub - 12: https://t.me/LearnoHub12 About the Teacher: Roshni Mukherjee, the Founder-Educator at LearnoHub has been building this free learning platform since 2011. She has been recognised as one of the 100 Women Achievers of India by the Ministry of Women & Child Development and felicitated by the President of India in 2016. Roshni has been invited by Google to speak at Global Education Symposium 2017 held at Google Headquarters, California. Limca Book of Records also recognized our work. Watch Roshni's Tedx Talk to know more about her journey: https://www.youtube.com/watch?v=v2sW_... Join us and let us together build this Free Learning Platform! We will surely ensure that you enjoy the real learning with us. Copyright © All rights reserved. LearnoHub | ExamFear Education